4x^2/3+5x=0

Solution for 4x^2/3+5x=0 equation:

4x^2/3+5x=0

We multiply all the terms by the denominator


4x^2+5x*3=0

Wy multiply elements

4x^2+15x=0

a = 4; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·4·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*4}=\frac{-30}{8}
=-3+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*4}=\frac{0}{8}
=0
$